WebExplanation for the correct option: Find the interval of S: Given, f ( x) = sin x - 3 cos x + 1. As we know, The range of the function f ( x) = a cos x + b sin x + c is: c – ( a 2 + b 2) ≤ f ( x) ≤ c + ( a 2 + b 2) Here, a = - 3, b = 1, c = 1. Now, c – ( a 2 + b 2) = 1 – ( 3 + 1) = 1 – 2 = - 1. Web`or, x = n*pi + pi/6` `` See eNotes Ad-Free. Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions …

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WebWe have: $$ -\sqrt{3}\sin x + \cos x=\\ =2\left(-\frac{\sqrt{3}}{2}\sin x + \frac{1}{2}\cos x\right)=\\ =2\left(\cos\frac{5\pi}{6}\sin x + \sin\frac{5\pi}{6}\cos x ... WebIf f:R→S, defined by f(x)=sinx− 3cosx+1, is onto, then the interval of S is A [0,1] B [−1,1] C [0,3] D [−1,3] Medium Solution Verified by Toppr Correct option is D) f(x)=sinx− 3cosx+1=2( 21sinx− 213cosx+1)=2(sin(x− 3π))+1Weknowthat−1≤sin(x− 3π)≤1⇒−2≤2sin(x− 3π)≤2⇒−1≤2sin(x− 3π)+1≤3rangeoff(x)=S=[−1,3]Hence,TheoptinDisthecorrectanswer. hotel avery boston ma

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WebWrite sinx+sin3x as a product. Hence,find all angles x in the interval [0,2π] that satisfy sinx+ sin3x −cosx = 0 ... x ∈ {12π, 125π, 2π, 23π} Explanation: First you should be ... Focusing on R+ by parity ( f is odd). Using the fact that −x−3 ≤ 3sinx+ xcosx ≤ x+ 3 you get f … WebCorrect option is B) The given function is onto. f(x)=sinx− 3cosx+1. ⇒f(x)=2sin(x− 3π)+1. The minimum value =−1 and maximum value =3. Therefore, S must in the interval [−1,3] … WebThe range of the function f(x) = [x] − x is _____ . Q. The range of f (x) = x + 5 is. Q. Let {x} denote the fractional part of x. Then lim x ... hotel avisa comfort inn