WebAlgebra. Find the Vertex Form f (x)=-x^2-4x-6. f (x) = −x2 − 4x − 6 f ( x) = - x 2 - 4 x - 6. Write f (x) = −x2 −4x−6 f ( x) = - x 2 - 4 x - 6 as an equation. y = −x2 −4x−6 y = - x 2 - 4 … Web👉 Learn how to graph quadratic equations in vertex form. A quadratic equation is an equation of the form y = ax^2 + bx + c, where a, b and c are constants. ...
Quadratic Functions in Standard Form - Turito - Converting …
WebFinal answer. Transcribed image text: A quadratic function f is given. f (x) = x2 +6x+8 (a) Express f in standard form. f (x) = (b) Find the vertex and x - and y -intercepts of f. (If an answer does not exist, enter DNE.) vertex (x,y) = ( x-intercepts (x,y) = (x) (smaller x-value) (x,y) = (x) (larger x-value) y-intercept (x,y) = ( x) Previous ... WebWhen x-4 = 0 (i.e. when x =4) you are left with just y=21 in the equation: because 4-4=0 0^2=0 -3(0)=0 This leaves the equation looking like y=0+21 Then you know that when … green tea to reduce belly fat
Find the Vertex f(x)=x^2-10x Mathway
WebMay 20, 2024 · First of all, you need to complete the square of \(x\) and this could be done as follows: f(x)=8[x^2+0.5x] =8[x^2 + 0.5x + (0.5/2)^2 - (0.5/2)^2] =8[(x^2 + 0.5x +1/16) - 1/16] =8[(x+0.25)^2 - 1/16] And our parabola has the vertex form of this: and according to the chart I attached, the vertex is (-0.25,-0.5) Web84K views 10 years ago How to graph a Quadratic in Vertex Form 👉 Learn how to graph quadratic equations in vertex form. A quadratic equation is an equation of the form y = ax^2 + bx + c,... WebWe know that the formula to calculate the x-coordinate of a vertex is -b/2a. Hence, h = - (-6)/2 (3) h = 6/6 = 1 Therefore, the x-coordinate of a vertex is 1. Now, we need to find the y-coordinate of a vertex. (i.e.) k. To get the value of the y-coordinate, substitute x =1 in the given equation y = 3x2-6x+1. Hence, y-coordinate (k) = 3 (1)2-6 (1)+1 green tea to poop